Solve (5xy)(-4y^3)(-2x^2y)=

$$( 5 x y ) ( - 4 y ^ { 3 } ) ( - 2 x ^ { 2 } y ) =$$

Evaluate

$$40x^{3}y^{5}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$5x^{3}y\left(-4\right)y^{3}\left(-2\right)y$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$5x^{3}y^{4}\left(-4\right)\left(-2\right)y$$

To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.

$$5x^{3}y^{5}\left(-4\right)\left(-2\right)$$

Multiply 5 and -4 to get -20.

$$-20x^{3}y^{5}\left(-2\right)$$

Multiply -20 and -2 to get 40.

$$40x^{3}y^{5}$$

Differentiate w.r.t. x

$$120x^{2}y^{5}$$