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5x-7=2\sqrt{3} 5x-7=-2\sqrt{3}
Take the square root of both sides of the equation.
5x-7-\left(-7\right)=2\sqrt{3}-\left(-7\right) 5x-7-\left(-7\right)=-2\sqrt{3}-\left(-7\right)
Add 7 to both sides of the equation.
5x=2\sqrt{3}-\left(-7\right) 5x=-2\sqrt{3}-\left(-7\right)
Subtracting -7 from itself leaves 0.
5x=2\sqrt{3}+7
Subtract -7 from 2\sqrt{3}.
5x=7-2\sqrt{3}
Subtract -7 from -2\sqrt{3}.
\frac{5x}{5}=\frac{2\sqrt{3}+7}{5} \frac{5x}{5}=\frac{7-2\sqrt{3}}{5}
Divide both sides by 5.
x=\frac{2\sqrt{3}+7}{5} x=\frac{7-2\sqrt{3}}{5}
Dividing by 5 undoes the multiplication by 5.