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5x-1=\frac{1}{3} 5x-1=-\frac{1}{3}
Take the square root of both sides of the equation.
5x-1-\left(-1\right)=\frac{1}{3}-\left(-1\right) 5x-1-\left(-1\right)=-\frac{1}{3}-\left(-1\right)
Add 1 to both sides of the equation.
5x=\frac{1}{3}-\left(-1\right) 5x=-\frac{1}{3}-\left(-1\right)
Subtracting -1 from itself leaves 0.
5x=\frac{4}{3}
Subtract -1 from \frac{1}{3}.
5x=\frac{2}{3}
Subtract -1 from -\frac{1}{3}.
\frac{5x}{5}=\frac{\frac{4}{3}}{5} \frac{5x}{5}=\frac{\frac{2}{3}}{5}
Divide both sides by 5.
x=\frac{\frac{4}{3}}{5} x=\frac{\frac{2}{3}}{5}
Dividing by 5 undoes the multiplication by 5.
x=\frac{4}{15}
Divide \frac{4}{3} by 5.
x=\frac{2}{15}
Divide \frac{2}{3} by 5.
x=\frac{4}{15} x=\frac{2}{15}
The equation is now solved.