Solve (5t_{6}+3+a+b-a)+20=3.05

$$( 5 t _ { 6 } + 3 + a + b - a ) + 20 = 3.05$$

Solve for b

$$b=-5t_{6}-19.95$$

Solution Steps

Combine a and -a to get 0.

$$5t_{6}+3+b+20=3.05$$

Add 3 and 20 to get 23.

$$5t_{6}+23+b=3.05$$

Subtract 5t_{6} from both sides.

$$23+b=3.05-5t_{6}$$

Subtract 23 from both sides.

$$b=3.05-5t_{6}-23$$

Subtract 23 from 3.05 to get -19.95.

$$b=-19.95-5t_{6}$$

Solve for a

$$a\in \mathrm{R}$$

$$t_{6}=-\frac{b}{5}-\frac{399}{100}$$