Solve (5a^2+4)^2=

$$( 5 a ^ { 2 } + 4 ) ^ { 2 } =$$

Evaluate

$$\left(5a^{2}+4\right)^{2}$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(5a^{2}+4\right)^{2}.

$$25\left(a^{2}\right)^{2}+40a^{2}+16$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$25a^{4}+40a^{2}+16$$

Expand

$$25a^{4}+40a^{2}+16$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(5a^{2}+4\right)^{2}.

$$25\left(a^{2}\right)^{2}+40a^{2}+16$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$25a^{4}+40a^{2}+16$$