Solve (5-a)x+4y-1=0

$$( 5 - a ) x + 4 y - 1 = 0$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{5x+4y-1}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&y=\frac{1}{4}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5-a by x.

$$5x-ax+4y-1=0$$

Subtract 5x from both sides. Anything subtracted from zero gives its negation.

$$-ax+4y-1=-5x$$

Subtract 4y from both sides.

$$-ax-1=-5x-4y$$

Add 1 to both sides.

$$-ax=-5x-4y+1$$

The equation is in standard form.

$$\left(-x\right)a=1-4y-5x$$

Divide both sides by -x.

$$\frac{\left(-x\right)a}{-x}=\frac{1-4y-5x}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$a=\frac{1-4y-5x}{-x}$$

Divide -5x-4y+1 by -x.

$$a=-\frac{1-4y-5x}{x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{4y-1}{5-a}\text{, }&a\neq 5\\x\in \mathrm{C}\text{, }&y=\frac{1}{4}\text{ and }a=5\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5-a by x.

$$5x-ax+4y-1=0$$

Subtract 4y from both sides. Anything subtracted from zero gives its negation.

$$5x-ax-1=-4y$$

Add 1 to both sides.

$$5x-ax=-4y+1$$

Combine all terms containing x.

$$\left(5-a\right)x=-4y+1$$

The equation is in standard form.

$$\left(5-a\right)x=1-4y$$

Divide both sides by 5-a.

$$\frac{\left(5-a\right)x}{5-a}=\frac{1-4y}{5-a}$$

Dividing by 5-a undoes the multiplication by 5-a.

$$x=\frac{1-4y}{5-a}$$

Solve for a

$$\left\{\begin{matrix}a=\frac{5x+4y-1}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&y=\frac{1}{4}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5-a by x.

$$5x-ax+4y-1=0$$

Subtract 5x from both sides. Anything subtracted from zero gives its negation.

$$-ax+4y-1=-5x$$

Subtract 4y from both sides.

$$-ax-1=-5x-4y$$

Add 1 to both sides.

$$-ax=-5x-4y+1$$

The equation is in standard form.

$$\left(-x\right)a=1-4y-5x$$

Divide both sides by -x.

$$\frac{\left(-x\right)a}{-x}=\frac{1-4y-5x}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$a=\frac{1-4y-5x}{-x}$$

Divide -5x-4y+1 by -x.

$$a=-\frac{1-4y-5x}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{4y-1}{5-a}\text{, }&a\neq 5\\x\in \mathrm{R}\text{, }&y=\frac{1}{4}\text{ and }a=5\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5-a by x.

$$5x-ax+4y-1=0$$

Subtract 4y from both sides. Anything subtracted from zero gives its negation.

$$5x-ax-1=-4y$$

Add 1 to both sides.

$$5x-ax=-4y+1$$

Combine all terms containing x.

$$\left(5-a\right)x=-4y+1$$

The equation is in standard form.

$$\left(5-a\right)x=1-4y$$

Divide both sides by 5-a.

$$\frac{\left(5-a\right)x}{5-a}=\frac{1-4y}{5-a}$$

Dividing by 5-a undoes the multiplication by 5-a.

$$x=\frac{1-4y}{5-a}$$