Solve (5-8)=3/4(1-1k)

$$( 5 - 8 ) = \frac { 3 } { 4 } ( 1 - 1 k )$$

Solve for k

$$k=5$$

Steps for Solving Linear Equation

Subtract 8 from 5 to get -3.

$$-3=\frac{3}{4}\left(1-k\right)$$

Use the distributive property to multiply \frac{3}{4} by 1-k.

$$-3=\frac{3}{4}+\frac{3}{4}\left(-1\right)k$$

Multiply \frac{3}{4} and -1 to get -\frac{3}{4}.

$$-3=\frac{3}{4}-\frac{3}{4}k$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{4}-\frac{3}{4}k=-3$$

Subtract \frac{3}{4} from both sides.

$$-\frac{3}{4}k=-3-\frac{3}{4}$$

Convert -3 to fraction -\frac{12}{4}.

$$-\frac{3}{4}k=-\frac{12}{4}-\frac{3}{4}$$

Since -\frac{12}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{3}{4}k=\frac{-12-3}{4}$$

Subtract 3 from -12 to get -15.

$$-\frac{3}{4}k=-\frac{15}{4}$$

Multiply both sides by -\frac{4}{3}, the reciprocal of -\frac{3}{4}.

$$k=-\frac{15}{4}\left(-\frac{4}{3}\right)$$

Multiply -\frac{15}{4} times -\frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$k=\frac{-15\left(-4\right)}{4\times 3}$$

Do the multiplications in the fraction \frac{-15\left(-4\right)}{4\times 3}.

$$k=\frac{60}{12}$$

Divide 60 by 12 to get 5.

$$k=5$$