Solve (5-4)+3-(12-5*2)+(5+16div4)-5+(10-2^3)

$$( 5 - 4 ) + 3 - ( 12 - 5 * 2 ) + ( 5 + 16 \div 4 ) - 5 + ( 10 - 2 ^ { 3 } )$$

Evaluate

$$8$$

Solution Steps

Subtract 4 from 5 to get 1.

$$1+3-\left(12-5\times 2\right)+5+\frac{16}{4}-5+10-2^{3}$$

Add 1 and 3 to get 4.

$$4-\left(12-5\times 2\right)+5+\frac{16}{4}-5+10-2^{3}$$

Multiply 5 and 2 to get 10.

$$4-\left(12-10\right)+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 10 from 12 to get 2.

$$4-2+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 2 from 4 to get 2.

$$2+5+\frac{16}{4}-5+10-2^{3}$$

Add 2 and 5 to get 7.

$$7+\frac{16}{4}-5+10-2^{3}$$

Divide 16 by 4 to get 4.

$$7+4-5+10-2^{3}$$

Add 7 and 4 to get 11.

$$11-5+10-2^{3}$$

Subtract 5 from 11 to get 6.

$$6+10-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$6+10-8$$

Subtract 8 from 10 to get 2.

$$6+2$$

Add 6 and 2 to get 8.

$$8$$

Factor

$$2^{3}$$