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\frac{\frac{40}{8}-\frac{1}{8}}{\frac{3\times 4+1}{4}}-\frac{1}{2}
Convert 5 to fraction \frac{40}{8}.
\frac{\frac{40-1}{8}}{\frac{3\times 4+1}{4}}-\frac{1}{2}
Since \frac{40}{8} and \frac{1}{8} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{39}{8}}{\frac{3\times 4+1}{4}}-\frac{1}{2}
Subtract 1 from 40 to get 39.
\frac{\frac{39}{8}}{\frac{12+1}{4}}-\frac{1}{2}
Multiply 3 and 4 to get 12.
\frac{\frac{39}{8}}{\frac{13}{4}}-\frac{1}{2}
Add 12 and 1 to get 13.
\frac{39}{8}\times \frac{4}{13}-\frac{1}{2}
Divide \frac{39}{8} by \frac{13}{4} by multiplying \frac{39}{8} by the reciprocal of \frac{13}{4}.
\frac{39\times 4}{8\times 13}-\frac{1}{2}
Multiply \frac{39}{8} times \frac{4}{13} by multiplying numerator times numerator and denominator times denominator.
\frac{156}{104}-\frac{1}{2}
Do the multiplications in the fraction \frac{39\times 4}{8\times 13}.
\frac{3}{2}-\frac{1}{2}
Reduce the fraction \frac{156}{104} to lowest terms by extracting and canceling out 52.
\frac{3-1}{2}
Since \frac{3}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{2}{2}
Subtract 1 from 3 to get 2.
1
Divide 2 by 2 to get 1.