Solve (5-1/3)div14/5+11/3

$$( 5 - \frac { 1 } { 3 } ) \div \frac { 14 } { 5 } + 1 \frac { 1 } { 3 }$$

Evaluate

$$3$$

Solution Steps

Convert 5 to fraction \frac{15}{3}.

$$\frac{\frac{15}{3}-\frac{1}{3}}{\frac{14}{5}}+\frac{1\times 3+1}{3}$$

Since \frac{15}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{15-1}{3}}{\frac{14}{5}}+\frac{1\times 3+1}{3}$$

Subtract 1 from 15 to get 14.

$$\frac{\frac{14}{3}}{\frac{14}{5}}+\frac{1\times 3+1}{3}$$

Divide \frac{14}{3} by \frac{14}{5} by multiplying \frac{14}{3} by the reciprocal of \frac{14}{5}.

$$\frac{14}{3}\times \frac{5}{14}+\frac{1\times 3+1}{3}$$

Multiply \frac{14}{3} times \frac{5}{14} by multiplying numerator times numerator and denominator times denominator.

$$\frac{14\times 5}{3\times 14}+\frac{1\times 3+1}{3}$$

Cancel out 14 in both numerator and denominator.

$$\frac{5}{3}+\frac{1\times 3+1}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{5}{3}+\frac{3+1}{3}$$

Add 3 and 1 to get 4.

$$\frac{5}{3}+\frac{4}{3}$$

Since \frac{5}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{5+4}{3}$$

Add 5 and 4 to get 9.

$$\frac{9}{3}$$

Divide 9 by 3 to get 3.

$$3$$

Factor

$$3$$