Solve for f (complex solution)
f=\frac{e^{x}+1}{5x\left(e^{x}-1\right)}
\nexists n_{1}\in \mathrm{Z}\text{ : }x=2\pi n_{1}i
Solve for f
f=\frac{e^{x}+1}{5x\left(e^{x}-1\right)}
x\neq 0
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5xf=\frac{e^{x}+1}{e^{x}-1}
The equation is in standard form.
\frac{5xf}{5x}=\frac{e^{x}+1}{\left(e^{x}-1\right)\times 5x}
Divide both sides by 5x.
f=\frac{e^{x}+1}{\left(e^{x}-1\right)\times 5x}
Dividing by 5x undoes the multiplication by 5x.
f=\frac{e^{x}+1}{5x\left(e^{x}-1\right)}
Divide \frac{e^{x}+1}{e^{x}-1} by 5x.
5xf=\frac{e^{x}+1}{e^{x}-1}
The equation is in standard form.
\frac{5xf}{5x}=\frac{e^{x}+1}{\left(e^{x}-1\right)\times 5x}
Divide both sides by 5x.
f=\frac{e^{x}+1}{\left(e^{x}-1\right)\times 5x}
Dividing by 5x undoes the multiplication by 5x.
f=\frac{e^{x}+1}{5x\left(e^{x}-1\right)}
Divide \frac{e^{x}+1}{e^{x}-1} by 5x.
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