Solve (5*10^-2)^2(1.2)=(1.25*10^-2)^2V_{2}

$$( 5 \times 10 ^ { - 2 } ) ^ { 2 } ( 1.2 ) = ( 1.25 \times 10 ^ { - 2 } ) ^ { 2 } V _ { 2 }$$

Solve for V_2

$$V_{2}=19.2$$

Steps for Solving Linear Equation

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\left(5\times \frac{1}{100}\right)^{2}\times 1.2=\left(1.25\times 10^{-2}\right)^{2}V_{2}$$

Multiply 5 and \frac{1}{100} to get \frac{1}{20}.

$$\left(\frac{1}{20}\right)^{2}\times 1.2=\left(1.25\times 10^{-2}\right)^{2}V_{2}$$

Calculate \frac{1}{20} to the power of 2 and get \frac{1}{400}.

$$\frac{1}{400}\times 1.2=\left(1.25\times 10^{-2}\right)^{2}V_{2}$$

Multiply \frac{1}{400} and 1.2 to get \frac{3}{1000}.

$$\frac{3}{1000}=\left(1.25\times 10^{-2}\right)^{2}V_{2}$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{3}{1000}=\left(1.25\times \frac{1}{100}\right)^{2}V_{2}$$

Multiply 1.25 and \frac{1}{100} to get \frac{1}{80}.

$$\frac{3}{1000}=\left(\frac{1}{80}\right)^{2}V_{2}$$

Calculate \frac{1}{80} to the power of 2 and get \frac{1}{6400}.

$$\frac{3}{1000}=\frac{1}{6400}V_{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{6400}V_{2}=\frac{3}{1000}$$

Multiply both sides by 6400, the reciprocal of \frac{1}{6400}.

$$V_{2}=\frac{3}{1000}\times 6400$$

Multiply \frac{3}{1000} and 6400 to get \frac{96}{5}.

$$V_{2}=\frac{96}{5}$$