Solve (5*43+10^4)-(3*2*10^3)^-3

$$( 5 \cdot 43 + 10 ^ { 4 } ) - ( 3 \cdot 2 \times 10 ^ { 3 } ) ^ { - 3 }$$

Evaluate

$$\frac{2206439999999999}{216000000000}\approx 10215$$

Solution Steps

Multiply 5 and 43 to get 215.

$$215+10^{4}-\left(3\times 2\times 10^{3}\right)^{-3}$$

Calculate 10 to the power of 4 and get 10000.

$$215+10000-\left(3\times 2\times 10^{3}\right)^{-3}$$

Add 215 and 10000 to get 10215.

$$10215-\left(3\times 2\times 10^{3}\right)^{-3}$$

Multiply 3 and 2 to get 6.

$$10215-\left(6\times 10^{3}\right)^{-3}$$

Calculate 10 to the power of 3 and get 1000.

$$10215-\left(6\times 1000\right)^{-3}$$

Multiply 6 and 1000 to get 6000.

$$10215-6000^{-3}$$

Calculate 6000 to the power of -3 and get \frac{1}{216000000000}.

$$10215-\frac{1}{216000000000}$$

Subtract \frac{1}{216000000000} from 10215 to get \frac{2206439999999999}{216000000000}.

$$\frac{2206439999999999}{216000000000}$$

Factor

$$\frac{149 \cdot 631 \cdot 1543 \cdot 15209347}{2 ^ {12} \cdot 3 ^ {3} \cdot 5 ^ {9}} = 10214\frac{215999999999}{216000000000} = 10214.999999999995$$