Solve (5^0+6^-1)*3^3

$$( 5 ^ { 0 } + 6 ^ { - 1 } ) \times 3 ^ { 3 }$$

Evaluate

$$\frac{63}{2}=31.5$$

Solution Steps

Calculate 5 to the power of 0 and get 1.

$$\left(1+6^{-1}\right)\times 3^{3}$$

Calculate 6 to the power of -1 and get \frac{1}{6}.

$$\left(1+\frac{1}{6}\right)\times 3^{3}$$

Add 1 and \frac{1}{6} to get \frac{7}{6}.

$$\frac{7}{6}\times 3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{7}{6}\times 27$$

Multiply \frac{7}{6} and 27 to get \frac{63}{2}.

$$\frac{63}{2}$$

Factor

$$\frac{3 ^ {2} \cdot 7}{2} = 31\frac{1}{2} = 31.5$$