Solve (5+3*2:6-4)*(4:2-3+6):(7-8:2-2)^2

$$( 5 + 3 \cdot 2 : 6 - 4 ) \cdot ( 4 : 2 - 3 + 6 ) : ( 7 - 8 : 2 - 2 ) ^ { 2 }$$

Evaluate

$$10$$

Solution Steps

Multiply 3 and 2 to get 6.

$$\frac{\left(5+\frac{6}{6}-4\right)\left(\frac{4}{2}-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Divide 6 by 6 to get 1.

$$\frac{\left(5+1-4\right)\left(\frac{4}{2}-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Add 5 and 1 to get 6.

$$\frac{\left(6-4\right)\left(\frac{4}{2}-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Subtract 4 from 6 to get 2.

$$\frac{2\left(\frac{4}{2}-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Divide 4 by 2 to get 2.

$$\frac{2\left(2-3+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Subtract 3 from 2 to get -1.

$$\frac{2\left(-1+6\right)}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Add -1 and 6 to get 5.

$$\frac{2\times 5}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Multiply 2 and 5 to get 10.

$$\frac{10}{\left(7-\frac{8}{2}-2\right)^{2}}$$

Divide 8 by 2 to get 4.

$$\frac{10}{\left(7-4-2\right)^{2}}$$

Subtract 4 from 7 to get 3.

$$\frac{10}{\left(3-2\right)^{2}}$$

Subtract 2 from 3 to get 1.

$$\frac{10}{1^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{10}{1}$$

Anything divided by one gives itself.

$$10$$

Factor

$$2\times 5$$