Evaluate
250\sqrt{3}+1900\approx 2333.012701892
Expand
250 \sqrt{3} + 1900 = 2333.012701892
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25+250\sqrt{3}+625\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(5+25\sqrt{3}\right)^{2}.
25+250\sqrt{3}+625\times 3
The square of \sqrt{3} is 3.
25+250\sqrt{3}+1875
Multiply 625 and 3 to get 1875.
1900+250\sqrt{3}
Add 25 and 1875 to get 1900.
25+250\sqrt{3}+625\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(5+25\sqrt{3}\right)^{2}.
25+250\sqrt{3}+625\times 3
The square of \sqrt{3} is 3.
25+250\sqrt{3}+1875
Multiply 625 and 3 to get 1875.
1900+250\sqrt{3}
Add 25 and 1875 to get 1900.
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