Solve (5+2-3)^2:8+(3^2-2*3)-1

$$( 5 + 2 - 3 ) ^ { 2 } : 8 + ( 3 ^ { 2 } - 2 \times 3 ) - 1$$

Evaluate

$$4$$

Solution Steps

Add 5 and 2 to get 7.

$$\frac{\left(7-3\right)^{2}}{8}+3^{2}-2\times 3-1$$

Subtract 3 from 7 to get 4.

$$\frac{4^{2}}{8}+3^{2}-2\times 3-1$$

Calculate 4 to the power of 2 and get 16.

$$\frac{16}{8}+3^{2}-2\times 3-1$$

Divide 16 by 8 to get 2.

$$2+3^{2}-2\times 3-1$$

Calculate 3 to the power of 2 and get 9.

$$2+9-2\times 3-1$$

Multiply 2 and 3 to get 6.

$$2+9-6-1$$

Subtract 6 from 9 to get 3.

$$2+3-1$$

Add 2 and 3 to get 5.

$$5-1$$

Subtract 1 from 5 to get 4.

$$4$$

Factor

$$2^{2}$$