Solve (49-x)^2=x^2+49

$$( 49 - x ) ^ { 2 } = x ^ { 2 } + 49$$

Solve for x

$$x=24$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(49-x\right)^{2}.

$$2401-98x+x^{2}=x^{2}+49$$

Subtract x^{2} from both sides.

$$2401-98x+x^{2}-x^{2}=49$$

Combine x^{2} and -x^{2} to get 0.

$$2401-98x=49$$

Subtract 2401 from both sides.

$$-98x=49-2401$$

Subtract 2401 from 49 to get -2352.

$$-98x=-2352$$

Divide both sides by -98.

$$x=\frac{-2352}{-98}$$

Divide -2352 by -98 to get 24.

$$x=24$$