Solve (4x-3-6x)(10x-8)

$$( 4 x - 3 - 6 x ) ( 10 x - 8 )$$

Evaluate

$$24-14x-20x^{2}$$

Solution Steps

Combine 4x and -6x to get -2x.

$$\left(-2x-3\right)\left(10x-8\right)$$

Apply the distributive property by multiplying each term of -2x-3 by each term of 10x-8.

$$-20x^{2}+16x-30x+24$$

Combine 16x and -30x to get -14x.

$$-20x^{2}-14x+24$$

Expand

$$24-14x-20x^{2}$$

Solution Steps

Combine 4x and -6x to get -2x.

$$\left(-2x-3\right)\left(10x-8\right)$$

Apply the distributive property by multiplying each term of -2x-3 by each term of 10x-8.

$$-20x^{2}+16x-30x+24$$

Combine 16x and -30x to get -14x.

$$-20x^{2}-14x+24$$