Solve (4x-3)-3/4(8/3x+4/3)=

$$( 4 x - 3 ) - \frac { 3 } { 4 } ( \frac { 8 } { 3 } x + \frac { 4 } { 3 } ) =$$

Evaluate

$$2\left(x-2\right)$$

Solution Steps

Use the distributive property to multiply -\frac{3}{4} by \frac{8}{3}x+\frac{4}{3}.

$$4x-3-\frac{3}{4}\times \frac{8}{3}x-\frac{3}{4}\times \frac{4}{3}$$

Multiply -\frac{3}{4} times \frac{8}{3} by multiplying numerator times numerator and denominator times denominator.

$$4x-3+\frac{-3\times 8}{4\times 3}x-\frac{3}{4}\times \frac{4}{3}$$

Do the multiplications in the fraction \frac{-3\times 8}{4\times 3}.

$$4x-3+\frac{-24}{12}x-\frac{3}{4}\times \frac{4}{3}$$

Divide -24 by 12 to get -2.

$$4x-3-2x-\frac{3}{4}\times \frac{4}{3}$$

Multiply -\frac{3}{4} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$4x-3-2x+\frac{-3\times 4}{4\times 3}$$

Cancel out 4 in both numerator and denominator.

$$4x-3-2x+\frac{-3}{3}$$

Divide -3 by 3 to get -1.

$$4x-3-2x-1$$

Combine 4x and -2x to get 2x.

$$2x-3-1$$

Subtract 1 from -3 to get -4.

$$2x-4$$

Expand

$$2x-4$$

Solution Steps

Use the distributive property to multiply -\frac{3}{4} by \frac{8}{3}x+\frac{4}{3}.

$$4x-3-\frac{3}{4}\times \frac{8}{3}x-\frac{3}{4}\times \frac{4}{3}$$

Multiply -\frac{3}{4} times \frac{8}{3} by multiplying numerator times numerator and denominator times denominator.

$$4x-3+\frac{-3\times 8}{4\times 3}x-\frac{3}{4}\times \frac{4}{3}$$

Do the multiplications in the fraction \frac{-3\times 8}{4\times 3}.

$$4x-3+\frac{-24}{12}x-\frac{3}{4}\times \frac{4}{3}$$

Divide -24 by 12 to get -2.

$$4x-3-2x-\frac{3}{4}\times \frac{4}{3}$$

Multiply -\frac{3}{4} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$4x-3-2x+\frac{-3\times 4}{4\times 3}$$

Cancel out 4 in both numerator and denominator.

$$4x-3-2x+\frac{-3}{3}$$

Divide -3 by 3 to get -1.

$$4x-3-2x-1$$

Combine 4x and -2x to get 2x.

$$2x-3-1$$

Subtract 1 from -3 to get -4.

$$2x-4$$