Solve (4x-18)^2=9/16

$$( 4 x - 18 ) ^ { 2 } = \frac { 9 } { 16 }$$

Solve for x

$$x = \frac{75}{16} = 4\frac{11}{16} = 4.6875$$

$$x = \frac{69}{16} = 4\frac{5}{16} = 4.3125$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$4x-18=\frac{3}{4} 4x-18=-\frac{3}{4}$$

Add 18 to both sides of the equation.

$$4x-18-\left(-18\right)=\frac{3}{4}-\left(-18\right) 4x-18-\left(-18\right)=-\frac{3}{4}-\left(-18\right)$$

Subtracting -18 from itself leaves 0.

$$4x=\frac{3}{4}-\left(-18\right) 4x=-\frac{3}{4}-\left(-18\right)$$

Subtract -18 from \frac{3}{4}.

$$4x=\frac{75}{4}$$

Subtract -18 from -\frac{3}{4}.

$$4x=\frac{69}{4}$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{\frac{75}{4}}{4} \frac{4x}{4}=\frac{\frac{69}{4}}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{\frac{75}{4}}{4} x=\frac{\frac{69}{4}}{4}$$

Divide \frac{75}{4} by 4.

$$x=\frac{75}{16}$$

Divide \frac{69}{4} by 4.

$$x=\frac{69}{16}$$

The equation is now solved.

$$x=\frac{75}{16} x=\frac{69}{16}$$