Solve (4x)(16)(x)=4096

$$( 4 x ) ( 16 ) ( x ) = 4096$$

Solve for x

$$x=8$$

$$x=-8$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$4x^{2}\times 16=4096$$

Multiply 4 and 16 to get 64.

$$64x^{2}=4096$$

Divide both sides by 64.

$$x^{2}=\frac{4096}{64}$$

Divide 4096 by 64 to get 64.

$$x^{2}=64$$

Take the square root of both sides of the equation.

$$x=8 x=-8$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$4x^{2}\times 16=4096$$

Multiply 4 and 16 to get 64.

$$64x^{2}=4096$$

Subtract 4096 from both sides.

$$64x^{2}-4096=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 64 for a, 0 for b, and -4096 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 64\left(-4096\right)}}{2\times 64}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 64\left(-4096\right)}}{2\times 64}$$

Multiply -4 times 64.

$$x=\frac{0±\sqrt{-256\left(-4096\right)}}{2\times 64}$$

Multiply -256 times -4096.

$$x=\frac{0±\sqrt{1048576}}{2\times 64}$$

Take the square root of 1048576.

$$x=\frac{0±1024}{2\times 64}$$

Multiply 2 times 64.

$$x=\frac{0±1024}{128}$$

Now solve the equation x=\frac{0±1024}{128} when ± is plus. Divide 1024 by 128.

$$x=8$$

Now solve the equation x=\frac{0±1024}{128} when ± is minus. Divide -1024 by 128.

$$x=-8$$

The equation is now solved.

$$x=8 x=-8$$