Solve (4x)^2=11.34

$$( 4 x ) ^ { 2 } = 11.34$$

Solve for x

$$x=\frac{9\sqrt{14}}{40}\approx 0.841872912$$

$$x=-\frac{9\sqrt{14}}{40}\approx -0.841872912$$

Steps by Finding Square Root

Expand \left(4x\right)^{2}.

$$4^{2}x^{2}=11.34$$

Calculate 4 to the power of 2 and get 16.

$$16x^{2}=11.34$$

Divide both sides by 16.

$$x^{2}=\frac{11.34}{16}$$

Expand \frac{11.34}{16} by multiplying both numerator and the denominator by 100.

$$x^{2}=\frac{1134}{1600}$$

Reduce the fraction \frac{1134}{1600} to lowest terms by extracting and canceling out 2.

$$x^{2}=\frac{567}{800}$$

Take the square root of both sides of the equation.

$$x=\frac{9\sqrt{14}}{40} x=-\frac{9\sqrt{14}}{40}$$