Solve (4x^{2}-3x^{2}+6x^2)*(4x^4-5x^4+x^4)

$$( 4 x ^ { 2 } - 3 x ^ { 2 } + 6 x ^ { 2 } ) \cdot ( 4 x ^ { 4 } - 5 x ^ { 4 } + x ^ { 4 } )$$

Evaluate

$$0$$

Solution Steps

Combine 4x^{2} and -3x^{2} to get x^{2}.

$$\left(x^{2}+6x^{2}\right)\left(4x^{4}-5x^{4}+x^{4}\right)$$

Combine x^{2} and 6x^{2} to get 7x^{2}.

$$7x^{2}\left(4x^{4}-5x^{4}+x^{4}\right)$$

Combine 4x^{4} and -5x^{4} to get -x^{4}.

$$7x^{2}\left(-x^{4}+x^{4}\right)$$

Combine -x^{4} and x^{4} to get 0.

$$7x^{2}\times 0$$

Multiply 7 and 0 to get 0.

$$0x^{2}$$

Anything times zero gives zero.

$$0$$

Factor

$$0$$