Solve (4x+4)+(4x-5)

$$( 4 x + 4 ) + ( 4 x - 5 )$$

Evaluate

$$8x-1$$

Solution Steps

Combine 4x and 4x to get 8x.

$$8x+4-5$$

Subtract 5 from 4 to get -1.

$$8x-1$$

Differentiate w.r.t. x

$$8$$

Steps Using Derivative Rule for Sum

Combine 4x and 4x to get 8x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x+4-5)$$

Subtract 5 from 4 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x-1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$8x^{1-1}$$

Subtract 1 from 1.

$$8x^{0}$$

For any term t except 0, t^{0}=1.

$$8\times 1$$

For any term t, t\times 1=t and 1t=t.

$$8$$