Solve (4x+3)^2-3=(4x-3)(3+4x)=

$$( 4 x + 3 ) ^ { 2 } - 3 = ( 4 x - 3 ) ( 3 + 4 x ) =$$

Solve for x

$$x=-\frac{5}{8}=-0.625$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(4x+3\right)^{2}.

$$16x^{2}+24x+9-3=\left(4x-3\right)\left(3+4x\right)$$

Subtract 3 from 9 to get 6.

$$16x^{2}+24x+6=\left(4x-3\right)\left(3+4x\right)$$

Use the distributive property to multiply 4x-3 by 3+4x and combine like terms.

$$16x^{2}+24x+6=16x^{2}-9$$

Subtract 16x^{2} from both sides.

$$16x^{2}+24x+6-16x^{2}=-9$$

Combine 16x^{2} and -16x^{2} to get 0.

$$24x+6=-9$$

Subtract 6 from both sides.

$$24x=-9-6$$

Subtract 6 from -9 to get -15.

$$24x=-15$$

Divide both sides by 24.

$$x=\frac{-15}{24}$$

Reduce the fraction \frac{-15}{24} to lowest terms by extracting and canceling out 3.

$$x=-\frac{5}{8}$$