Solve (4k-3)(k-2)-4k(k+2)=-13

$$( 4 k - 3 ) ( k - 2 ) - 4 k ( k + 2 ) = - 13$$

Solve for k

$$k=1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 4k-3 by k-2 and combine like terms.

$$4k^{2}-11k+6-4k\left(k+2\right)=-13$$

Use the distributive property to multiply -4k by k+2.

$$4k^{2}-11k+6-4k^{2}-8k=-13$$

Combine 4k^{2} and -4k^{2} to get 0.

$$-11k+6-8k=-13$$

Combine -11k and -8k to get -19k.

$$-19k+6=-13$$

Subtract 6 from both sides.

$$-19k=-13-6$$

Subtract 6 from -13 to get -19.

$$-19k=-19$$

Divide both sides by -19.

$$k=\frac{-19}{-19}$$

Divide -19 by -19 to get 1.

$$k=1$$