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4iw+w^{2}=5
Use the distributive property to multiply 4i+w by w.
4iw+w^{2}-5=0
Subtract 5 from both sides.
w^{2}+4iw-5=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
w=\frac{-4i±\sqrt{\left(4i\right)^{2}-4\left(-5\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 4i for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
w=\frac{-4i±\sqrt{-16-4\left(-5\right)}}{2}
Square 4i.
w=\frac{-4i±\sqrt{-16+20}}{2}
Multiply -4 times -5.
w=\frac{-4i±\sqrt{4}}{2}
Add -16 to 20.
w=\frac{-4i±2}{2}
Take the square root of 4.
w=\frac{2-4i}{2}
Now solve the equation w=\frac{-4i±2}{2} when ± is plus. Add -4i to 2.
w=1-2i
Divide 2-4i by 2.
w=\frac{-2-4i}{2}
Now solve the equation w=\frac{-4i±2}{2} when ± is minus. Subtract 2 from -4i.
w=-1-2i
Divide -2-4i by 2.
w=1-2i w=-1-2i
The equation is now solved.
4iw+w^{2}=5
Use the distributive property to multiply 4i+w by w.
w^{2}+4iw=5
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
w^{2}+4iw+\left(2i\right)^{2}=5+\left(2i\right)^{2}
Divide 4i, the coefficient of the x term, by 2 to get 2i. Then add the square of 2i to both sides of the equation. This step makes the left hand side of the equation a perfect square.
w^{2}+4iw-4=5-4
Square 2i.
w^{2}+4iw-4=1
Add 5 to -4.
\left(w+2i\right)^{2}=1
Factor w^{2}+4iw-4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(w+2i\right)^{2}}=\sqrt{1}
Take the square root of both sides of the equation.
w+2i=1 w+2i=-1
Simplify.
w=1-2i w=-1-2i
Subtract 2i from both sides of the equation.