Solve (4c+5)+(2c-6)

$$( 4 c + 5 ) + ( 2 c - 6 )$$

Evaluate

$$6c-1$$

Solution Steps

Combine 4c and 2c to get 6c.

$$6c+5-6$$

Subtract 6 from 5 to get -1.

$$6c-1$$

Differentiate w.r.t. c

$$6$$

Steps Using Derivative Rule for Sum

Combine 4c and 2c to get 6c.

$$\frac{\mathrm{d}}{\mathrm{d}c}(6c+5-6)$$

Subtract 6 from 5 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}c}(6c-1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$6c^{1-1}$$

Subtract 1 from 1.

$$6c^{0}$$

For any term t except 0, t^{0}=1.

$$6\times 1$$

For any term t, t\times 1=t and 1t=t.

$$6$$