Solve for x
x = \frac{9}{2} = 4\frac{1}{2} = 4.5
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16-8x+x^{2}+\left(-\frac{1}{2}x+2\right)^{2}=\left(5-x\right)^{2}+\left(-\frac{1}{2}x+2\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4-x\right)^{2}.
16-8x+x^{2}+\frac{1}{4}x^{2}-2x+4=\left(5-x\right)^{2}+\left(-\frac{1}{2}x+2\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(-\frac{1}{2}x+2\right)^{2}.
16-8x+\frac{5}{4}x^{2}-2x+4=\left(5-x\right)^{2}+\left(-\frac{1}{2}x+2\right)^{2}
Combine x^{2} and \frac{1}{4}x^{2} to get \frac{5}{4}x^{2}.
16-10x+\frac{5}{4}x^{2}+4=\left(5-x\right)^{2}+\left(-\frac{1}{2}x+2\right)^{2}
Combine -8x and -2x to get -10x.
20-10x+\frac{5}{4}x^{2}=\left(5-x\right)^{2}+\left(-\frac{1}{2}x+2\right)^{2}
Add 16 and 4 to get 20.
20-10x+\frac{5}{4}x^{2}=25-10x+x^{2}+\left(-\frac{1}{2}x+2\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(5-x\right)^{2}.
20-10x+\frac{5}{4}x^{2}=25-10x+x^{2}+\frac{1}{4}x^{2}-2x+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(-\frac{1}{2}x+2\right)^{2}.
20-10x+\frac{5}{4}x^{2}=25-10x+\frac{5}{4}x^{2}-2x+4
Combine x^{2} and \frac{1}{4}x^{2} to get \frac{5}{4}x^{2}.
20-10x+\frac{5}{4}x^{2}=25-12x+\frac{5}{4}x^{2}+4
Combine -10x and -2x to get -12x.
20-10x+\frac{5}{4}x^{2}=29-12x+\frac{5}{4}x^{2}
Add 25 and 4 to get 29.
20-10x+\frac{5}{4}x^{2}+12x=29+\frac{5}{4}x^{2}
Add 12x to both sides.
20+2x+\frac{5}{4}x^{2}=29+\frac{5}{4}x^{2}
Combine -10x and 12x to get 2x.
20+2x+\frac{5}{4}x^{2}-\frac{5}{4}x^{2}=29
Subtract \frac{5}{4}x^{2} from both sides.
20+2x=29
Combine \frac{5}{4}x^{2} and -\frac{5}{4}x^{2} to get 0.
2x=29-20
Subtract 20 from both sides.
2x=9
Subtract 20 from 29 to get 9.
x=\frac{9}{2}
Divide both sides by 2.
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y = 3x + 4
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Matrix
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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