Solve (4-a)e^-2=3

$$( 4 - a ) e ^ { - 2 } = 3$$

Solve for a

$$a=-3e^{2}+4\approx -18.167168297$$

Steps for Solving Linear Equation

Use the distributive property to multiply 4-a by e^{-2}.

$$4e^{-2}-ae^{-2}=3$$

Subtract 4e^{-2} from both sides.

$$-ae^{-2}=3-4e^{-2}$$

The equation is in standard form.

$$\left(-\frac{1}{e^{2}}\right)a=-\frac{4}{e^{2}}+3$$

Divide both sides by -e^{-2}.

$$\frac{\left(-\frac{1}{e^{2}}\right)a}{-\frac{1}{e^{2}}}=\frac{-\frac{4}{e^{2}}+3}{-\frac{1}{e^{2}}}$$

Dividing by -e^{-2} undoes the multiplication by -e^{-2}.

$$a=\frac{-\frac{4}{e^{2}}+3}{-\frac{1}{e^{2}}}$$

Divide 3-\frac{4}{e^{2}} by -e^{-2}.

$$a=-3e^{2}+4$$