Solve (4-11y)^2-1=0

$$( 4 - 11 y ) ^ { 2 } - 1 = 0$$

Solve for y

$$y=\frac{3}{11}\approx 0.272727273$$

$$y=\frac{5}{11}\approx 0.454545455$$

Steps by Finding Square Root

Add 1 to both sides of the equation.

$$\left(-11y+4\right)^{2}-1+1=1$$

Subtracting 1 from itself leaves 0.

$$\left(-11y+4\right)^{2}=1$$

Take the square root of both sides of the equation.

$$-11y+4=1 -11y+4=-1$$

Subtract 4 from both sides of the equation.

$$-11y+4-4=1-4 -11y+4-4=-1-4$$

Subtracting 4 from itself leaves 0.

$$-11y=1-4 -11y=-1-4$$

Subtract 4 from 1.

$$-11y=-3$$

Subtract 4 from -1.

$$-11y=-5$$

Divide both sides by -11.

$$\frac{-11y}{-11}=-\frac{3}{-11} \frac{-11y}{-11}=-\frac{5}{-11}$$

Dividing by -11 undoes the multiplication by -11.

$$y=-\frac{3}{-11} y=-\frac{5}{-11}$$

Divide -3 by -11.

$$y=\frac{3}{11}$$

Divide -5 by -11.

$$y=\frac{5}{11}$$

The equation is now solved.

$$y=\frac{3}{11} y=\frac{5}{11}$$