Solve (4-1(6*2(3+4-2))-2)

$$( 4 - 1 ( 6 \cdot 2 ( 3 + 4 - 2 ) ) - 2 )$$

Evaluate

$$-58$$

Solution Steps

Multiply 1 and 6 to get 6.

$$4-6\times 2\left(3+4-2\right)-2$$

Multiply 6 and 2 to get 12.

$$4-12\left(3+4-2\right)-2$$

Add 3 and 4 to get 7.

$$4-12\left(7-2\right)-2$$

Subtract 2 from 7 to get 5.

$$4-12\times 5-2$$

Multiply 12 and 5 to get 60.

$$4-60-2$$

Subtract 60 from 4 to get -56.

$$-56-2$$

Subtract 2 from -56 to get -58.

$$-58$$

Factor

$$-58$$