Solve (4)2(y+2)-3(4y-1)=9(1-y)

$$( 4 ) 2 ( y + 2 ) - 3 ( 4 y - 1 ) = 9 ( 1 - y )$$

Solve for y

$$y=-2$$

Steps for Solving Linear Equation

Multiply 4 and 2 to get 8.

$$8\left(y+2\right)-3\left(4y-1\right)=9\left(1-y\right)$$

Use the distributive property to multiply 8 by y+2.

$$8y+16-3\left(4y-1\right)=9\left(1-y\right)$$

Use the distributive property to multiply -3 by 4y-1.

$$8y+16-12y+3=9\left(1-y\right)$$

Combine 8y and -12y to get -4y.

$$-4y+16+3=9\left(1-y\right)$$

Add 16 and 3 to get 19.

$$-4y+19=9\left(1-y\right)$$

Use the distributive property to multiply 9 by 1-y.

$$-4y+19=9-9y$$

Add 9y to both sides.

$$-4y+19+9y=9$$

Combine -4y and 9y to get 5y.

$$5y+19=9$$

Subtract 19 from both sides.

$$5y=9-19$$

Subtract 19 from 9 to get -10.

$$5y=-10$$

Divide both sides by 5.

$$y=\frac{-10}{5}$$

Divide -10 by 5 to get -2.

$$y=-2$$