Solve (4)(-2)^2*sqrt{(-4)^2}+sqrt[3]{(-4)^3}*(1/2)^2-sqrt{9}

$$( 4 ) ( - 2 ) ^ { 2 } \times \sqrt { ( - 4 ) ^ { 2 } } + \sqrt[ 3 ] { ( - 4 ) ^ { 3 } } \times ( \frac { 1 } { 2 } ) ^ { 2 } - \sqrt { 9 }$$

Evaluate

$$60$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$4\times 4\sqrt{\left(-4\right)^{2}}+\sqrt[3]{\left(-4\right)^{3}}\times \left(\frac{1}{2}\right)^{2}-\sqrt{9}$$

Multiply 4 and 4 to get 16.

$$16\sqrt{\left(-4\right)^{2}}+\sqrt[3]{\left(-4\right)^{3}}\times \left(\frac{1}{2}\right)^{2}-\sqrt{9}$$

Calculate -4 to the power of 2 and get 16.

$$16\sqrt{16}+\sqrt[3]{\left(-4\right)^{3}}\times \left(\frac{1}{2}\right)^{2}-\sqrt{9}$$

Calculate the square root of 16 and get 4.

$$16\times 4+\sqrt[3]{\left(-4\right)^{3}}\times \left(\frac{1}{2}\right)^{2}-\sqrt{9}$$

Multiply 16 and 4 to get 64.

$$64+\sqrt[3]{\left(-4\right)^{3}}\times \left(\frac{1}{2}\right)^{2}-\sqrt{9}$$

Calculate -4 to the power of 3 and get -64.

$$64+\sqrt[3]{-64}\times \left(\frac{1}{2}\right)^{2}-\sqrt{9}$$

Calculate \sqrt[3]{-64} and get -4.

$$64-4\times \left(\frac{1}{2}\right)^{2}-\sqrt{9}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$64-4\times \frac{1}{4}-\sqrt{9}$$

Multiply -4 and \frac{1}{4} to get -1.

$$64-1-\sqrt{9}$$

Subtract 1 from 64 to get 63.

$$63-\sqrt{9}$$

Calculate the square root of 9 and get 3.

$$63-3$$

Subtract 3 from 63 to get 60.

$$60$$

Factor

$$2^{2}\times 3\times 5$$