Solve (4)5/3x+4/3=11/3x-8/3

$$( 4 ) \frac { 5 } { 3 } x + \frac { 4 } { 3 } = \frac { 11 } { 3 } x - \frac { 8 } { 3 }$$

Solve for x

$$x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$$

Steps for Solving Linear Equation

Express 4\times \frac{5}{3} as a single fraction.

$$\frac{4\times 5}{3}x+\frac{4}{3}=\frac{11}{3}x-\frac{8}{3}$$

Multiply 4 and 5 to get 20.

$$\frac{20}{3}x+\frac{4}{3}=\frac{11}{3}x-\frac{8}{3}$$

Subtract \frac{11}{3}x from both sides.

$$\frac{20}{3}x+\frac{4}{3}-\frac{11}{3}x=-\frac{8}{3}$$

Combine \frac{20}{3}x and -\frac{11}{3}x to get 3x.

$$3x+\frac{4}{3}=-\frac{8}{3}$$

Subtract \frac{4}{3} from both sides.

$$3x=-\frac{8}{3}-\frac{4}{3}$$

Since -\frac{8}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$3x=\frac{-8-4}{3}$$

Subtract 4 from -8 to get -12.

$$3x=\frac{-12}{3}$$

Divide -12 by 3 to get -4.

$$3x=-4$$

Divide both sides by 3.

$$x=\frac{-4}{3}$$

Fraction \frac{-4}{3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$x=-\frac{4}{3}$$