Solve (4)^2-4(8)(h)<0

$$( 4 ) ^ { 2 } - 4 ( 8 ) ( h ) < 0$$

Solve for h

$$h>\frac{1}{2}$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16-4\times 8h<0$$

Multiply 4 and 8 to get 32.

$$16-32h<0$$

Subtract 16 from both sides. Anything subtracted from zero gives its negation.

$$-32h<-16$$

Divide both sides by -32. Since -32 is negative, the inequality direction is changed.

$$h>\frac{-16}{-32}$$

Reduce the fraction \frac{-16}{-32} to lowest terms by extracting and canceling out -16.

$$h>\frac{1}{2}$$