Solve (4)+23-10*3+(10*[4+3*2]-1):17+14:2-2

$$( 4 ) + 23 - 10 \cdot 3 + ( 10 \cdot [ 4 + 3 \cdot 2 ] - 1 ) : 17 + 14 : 2 - 2$$

Evaluate

$$\frac{133}{17}\approx 7.823529412$$

Solution Steps

Add 4 and 23 to get 27.

$$27-10\times 3+\frac{10\left(4+3\times 2\right)-1}{17}+\frac{14}{2}-2$$

Multiply 10 and 3 to get 30.

$$27-30+\frac{10\left(4+3\times 2\right)-1}{17}+\frac{14}{2}-2$$

Subtract 30 from 27 to get -3.

$$-3+\frac{10\left(4+3\times 2\right)-1}{17}+\frac{14}{2}-2$$

Multiply 3 and 2 to get 6.

$$-3+\frac{10\left(4+6\right)-1}{17}+\frac{14}{2}-2$$

Add 4 and 6 to get 10.

$$-3+\frac{10\times 10-1}{17}+\frac{14}{2}-2$$

Multiply 10 and 10 to get 100.

$$-3+\frac{100-1}{17}+\frac{14}{2}-2$$

Subtract 1 from 100 to get 99.

$$-3+\frac{99}{17}+\frac{14}{2}-2$$

Convert -3 to fraction -\frac{51}{17}.

$$-\frac{51}{17}+\frac{99}{17}+\frac{14}{2}-2$$

Since -\frac{51}{17} and \frac{99}{17} have the same denominator, add them by adding their numerators.

$$\frac{-51+99}{17}+\frac{14}{2}-2$$

Add -51 and 99 to get 48.

$$\frac{48}{17}+\frac{14}{2}-2$$

Divide 14 by 2 to get 7.

$$\frac{48}{17}+7-2$$

Convert 7 to fraction \frac{119}{17}.

$$\frac{48}{17}+\frac{119}{17}-2$$

Since \frac{48}{17} and \frac{119}{17} have the same denominator, add them by adding their numerators.

$$\frac{48+119}{17}-2$$

Add 48 and 119 to get 167.

$$\frac{167}{17}-2$$

Convert 2 to fraction \frac{34}{17}.

$$\frac{167}{17}-\frac{34}{17}$$

Since \frac{167}{17} and \frac{34}{17} have the same denominator, subtract them by subtracting their numerators.

$$\frac{167-34}{17}$$

Subtract 34 from 167 to get 133.

$$\frac{133}{17}$$

Factor

$$\frac{7 \cdot 19}{17} = 7\frac{14}{17} = 7.823529411764706$$