Solve (4*10^3)^3*(-0125*10^2)^2=

$$( 4 \times 10 ^ { 3 } ) ^ { 3 } \cdot ( - 0125 \times 10 ^ { 2 } ) ^ { 2 } =$$

Evaluate

$$0$$

Solution Steps

Calculate 10 to the power of 3 and get 1000.

$$\left(4\times 1000\right)^{3}\times \left(0\times 125\times 10^{2}\right)^{2}$$

Multiply 4 and 1000 to get 4000.

$$4000^{3}\times \left(0\times 125\times 10^{2}\right)^{2}$$

Calculate 4000 to the power of 3 and get 64000000000.

$$64000000000\times \left(0\times 125\times 10^{2}\right)^{2}$$

Multiply 0 and 125 to get 0.

$$64000000000\times \left(0\times 10^{2}\right)^{2}$$

Calculate 10 to the power of 2 and get 100.

$$64000000000\times \left(0\times 100\right)^{2}$$

Multiply 0 and 100 to get 0.

$$64000000000\times 0^{2}$$

Calculate 0 to the power of 2 and get 0.

$$64000000000\times 0$$

Multiply 64000000000 and 0 to get 0.

$$0$$

Factor

$$0$$