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16\left(\sqrt{3}\right)^{2}-48\sqrt{3}+36
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4\sqrt{3}-6\right)^{2}.
16\times 3-48\sqrt{3}+36
The square of \sqrt{3} is 3.
48-48\sqrt{3}+36
Multiply 16 and 3 to get 48.
84-48\sqrt{3}
Add 48 and 36 to get 84.
16\left(\sqrt{3}\right)^{2}-48\sqrt{3}+36
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4\sqrt{3}-6\right)^{2}.
16\times 3-48\sqrt{3}+36
The square of \sqrt{3} is 3.
48-48\sqrt{3}+36
Multiply 16 and 3 to get 48.
84-48\sqrt{3}
Add 48 and 36 to get 84.