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4\left(\sqrt{10}\right)^{2}+8\sqrt{10}-3\sqrt{10}-6
Apply the distributive property by multiplying each term of 4\sqrt{10}-3 by each term of \sqrt{10}+2.
4\times 10+8\sqrt{10}-3\sqrt{10}-6
The square of \sqrt{10} is 10.
40+8\sqrt{10}-3\sqrt{10}-6
Multiply 4 and 10 to get 40.
40+5\sqrt{10}-6
Combine 8\sqrt{10} and -3\sqrt{10} to get 5\sqrt{10}.
34+5\sqrt{10}
Subtract 6 from 40 to get 34.