Solve (42/5-2,9)*61/3

$$( 4 \frac { 2 } { 5 } - 2,9 ) \cdot 6 \frac { 1 } { 3 }$$

Evaluate

$$9,5$$

Solution Steps

Multiply 4 and 5 to get 20.

$$\left(\frac{20+2}{5}-2,9\right)\times \frac{6\times 3+1}{3}$$

Add 20 and 2 to get 22.

$$\left(\frac{22}{5}-2,9\right)\times \frac{6\times 3+1}{3}$$

Convert decimal number 2,9 to fraction \frac{29}{10}.

$$\left(\frac{22}{5}-\frac{29}{10}\right)\times \frac{6\times 3+1}{3}$$

Least common multiple of 5 and 10 is 10. Convert \frac{22}{5} and \frac{29}{10} to fractions with denominator 10.

$$\left(\frac{44}{10}-\frac{29}{10}\right)\times \frac{6\times 3+1}{3}$$

Since \frac{44}{10} and \frac{29}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{44-29}{10}\times \frac{6\times 3+1}{3}$$

Subtract 29 from 44 to get 15.

$$\frac{15}{10}\times \frac{6\times 3+1}{3}$$

Reduce the fraction \frac{15}{10} to lowest terms by extracting and canceling out 5.

$$\frac{3}{2}\times \frac{6\times 3+1}{3}$$

Multiply 6 and 3 to get 18.

$$\frac{3}{2}\times \frac{18+1}{3}$$

Add 18 and 1 to get 19.

$$\frac{3}{2}\times \frac{19}{3}$$

Multiply \frac{3}{2} times \frac{19}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 19}{2\times 3}$$

Cancel out 3 in both numerator and denominator.

$$\frac{19}{2}$$

Factor

$$\frac{19}{2} = 9\frac{1}{2} = 9.5$$