Solve (4^{3}*4^2*4)div(2^4*2^3*2^2)

$$( 4 ^ { 3 } \times 4 ^ { 2 } \times 4 ) \div ( 2 ^ { 4 } \times 2 ^ { 3 } \times 2 ^ { 2 } )$$

Evaluate

$$8$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$\frac{4^{5}\times 4}{2^{4}\times 2^{3}\times 2^{2}}$$

To multiply powers of the same base, add their exponents. Add 5 and 1 to get 6.

$$\frac{4^{6}}{2^{4}\times 2^{3}\times 2^{2}}$$

To multiply powers of the same base, add their exponents. Add 4 and 3 to get 7.

$$\frac{4^{6}}{2^{7}\times 2^{2}}$$

To multiply powers of the same base, add their exponents. Add 7 and 2 to get 9.

$$\frac{4^{6}}{2^{9}}$$

Calculate 4 to the power of 6 and get 4096.

$$\frac{4096}{2^{9}}$$

Calculate 2 to the power of 9 and get 512.

$$\frac{4096}{512}$$

Divide 4096 by 512 to get 8.

$$8$$

Factor

$$2^{3}$$