Solve (4^2)^3*(8^-3)^2=

$$( 4 ^ { 2 } ) ^ { 3 } \cdot ( 8 ^ { - 3 } ) ^ { 2 } =$$

Evaluate

$$\frac{1}{64}=0.015625$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$4^{6}\times \left(8^{-3}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply -3 and 2 to get -6.

$$4^{6}\times 8^{-6}$$

Calculate 4 to the power of 6 and get 4096.

$$4096\times 8^{-6}$$

Calculate 8 to the power of -6 and get \frac{1}{262144}.

$$4096\times \frac{1}{262144}$$

Multiply 4096 and \frac{1}{262144} to get \frac{1}{64}.

$$\frac{1}{64}$$

Factor

$$\frac{1}{2 ^ {6}} = 0.015625$$