Solve (4^2)^-5*4(4^-3)^-3

$$( 4 ^ { 2 } ) ^ { - 5 } \times 4 ( 4 ^ { - 3 } ) ^ { - 3 }$$

Evaluate

$$1$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and -5 to get -10.

$$4^{-10}\times 4\times \left(4^{-3}\right)^{-3}$$

To raise a power to another power, multiply the exponents. Multiply -3 and -3 to get 9.

$$4^{-10}\times 4\times 4^{9}$$

To multiply powers of the same base, add their exponents. Add -10 and 1 to get -9.

$$4^{-9}\times 4^{9}$$

Multiply 4^{-9} and 4^{9} to get 1.

$$1$$

Factor

$$1$$