Solve (4^2)^-3*4(4^-3)^-3

$$( 4 ^ { 2 } ) ^ { - 3 } \times 4 ( 4 ^ { - 3 } ) ^ { - 3 }$$

Evaluate

$$256$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and -3 to get -6.

$$4^{-6}\times 4\times \left(4^{-3}\right)^{-3}$$

To raise a power to another power, multiply the exponents. Multiply -3 and -3 to get 9.

$$4^{-6}\times 4\times 4^{9}$$

To multiply powers of the same base, add their exponents. Add -6 and 1 to get -5.

$$4^{-5}\times 4^{9}$$

To multiply powers of the same base, add their exponents. Add -5 and 9 to get 4.

$$4^{4}$$

Calculate 4 to the power of 4 and get 256.

$$256$$

Factor

$$2^{8}$$