Solve (4^2*15div(13-3))+2*11+3^3*2

$$( 4 ^ { 2 } \times 15 \div ( 13 - 3 ) ) + 2 \times 11 + 3 ^ { 3 } \times 2$$

Evaluate

$$100$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{16\times 15}{13-3}+2\times 11+3^{3}\times 2$$

Multiply 16 and 15 to get 240.

$$\frac{240}{13-3}+2\times 11+3^{3}\times 2$$

Subtract 3 from 13 to get 10.

$$\frac{240}{10}+2\times 11+3^{3}\times 2$$

Divide 240 by 10 to get 24.

$$24+2\times 11+3^{3}\times 2$$

Multiply 2 and 11 to get 22.

$$24+22+3^{3}\times 2$$

Add 24 and 22 to get 46.

$$46+3^{3}\times 2$$

Calculate 3 to the power of 3 and get 27.

$$46+27\times 2$$

Multiply 27 and 2 to get 54.

$$46+54$$

Add 46 and 54 to get 100.

$$100$$

Factor

$$2^{2}\times 5^{2}$$