Solve (4^{2}+3*2^2-5^2)^3:3^2

$$( 4 ^ { 2 } + 3 \cdot 2 ^ { 2 } - 5 ^ { 2 } ) ^ { 3 } : 3 ^ { 2 }$$

Evaluate

$$3$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{\left(16+3\times 2^{2}-5^{2}\right)^{3}}{3^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{\left(16+3\times 4-5^{2}\right)^{3}}{3^{2}}$$

Multiply 3 and 4 to get 12.

$$\frac{\left(16+12-5^{2}\right)^{3}}{3^{2}}$$

Add 16 and 12 to get 28.

$$\frac{\left(28-5^{2}\right)^{3}}{3^{2}}$$

Calculate 5 to the power of 2 and get 25.

$$\frac{\left(28-25\right)^{3}}{3^{2}}$$

Subtract 25 from 28 to get 3.

$$\frac{3^{3}}{3^{2}}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{27}{3^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{27}{9}$$

Divide 27 by 9 to get 3.

$$3$$

Factor

$$3$$