Solve (4+3),(-7)-1+4-5-(-3)^2

$$( 4 + 3 ) , ( - 7 ) - 1 + 4 - 5 - ( - 3 ) ^ { 2 }$$

Sort

$$-18,7$$

Solution Steps

Add 4 and 3 to get 7.

$$sort(7,-7-1+4-5-\left(-3\right)^{2})$$

Subtract 1 from -7 to get -8.

$$sort(7,-8+4-5-\left(-3\right)^{2})$$

Add -8 and 4 to get -4.

$$sort(7,-4-5-\left(-3\right)^{2})$$

Subtract 5 from -4 to get -9.

$$sort(7,-9-\left(-3\right)^{2})$$

Calculate -3 to the power of 2 and get 9.

$$sort(7,-9-9)$$

Subtract 9 from -9 to get -18.

$$sort(7,-18)$$

To sort the list, start from a single element 7.

$$7$$

Insert -18 to the appropriate location in the new list.

$$-18,7$$

Evaluate

$$7,-18$$