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20-4\sqrt{3}+10\sqrt{3}-2\left(\sqrt{3}\right)^{2}
Apply the distributive property by multiplying each term of 4+2\sqrt{3} by each term of 5-\sqrt{3}.
20+6\sqrt{3}-2\left(\sqrt{3}\right)^{2}
Combine -4\sqrt{3} and 10\sqrt{3} to get 6\sqrt{3}.
20+6\sqrt{3}-2\times 3
The square of \sqrt{3} is 3.
20+6\sqrt{3}-6
Multiply -2 and 3 to get -6.
14+6\sqrt{3}
Subtract 6 from 20 to get 14.